How do you divide #\frac { 24m ^ { 3} + 20m ^ { 2} + 24m } { 4m ^ { 2} }#?

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Answer 1 · 2017-07-06T01:59:51

#(6m^2+5m+6)/(m)#

Begin by factoring the numerator. We can factor out a #4m#.

#(4m(6m^2+5m+6))/(4m^2)#

We can simplify #(4m)/(4m^2)# which gives us #m#. We then rewrite the expression like this:

#(6m^2+5m+6)/(m)#

Answer 2 · 2017-07-06T08:50:45

#6m+5+6/m#

#(24m^3+20m^2+24m)/(4m^2)#

#=(24m^3)/(4m^2)+(20m^2)/(4m^2)+(24m)/(4m^2)#

#=6m+5+6/m#