How do you divide #\frac { 2v + 5} { 4v ^ { 4} - v ^ { 2} } \div \frac { 2v + 5} { 4v ^ { 2} - 1}#?

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Answer 1 · 2017-11-03T17:53:37

#1/v^2#

The first step is to factorise as far as possible:

#(2v+5)/(v^2(4v^2-1)) div ((2v+5))/((2v+1)(2v-1))#

To divide, multiply by the reciprocal:

#=((2v+5))/(v^2(2v+1)(2v-1)) xx((2v+1)(2v-1))/ ((2v+5))#

Cancel factors which are the same:

#=cancel((2v+5))/(v^2cancel((2v+1)(2v-1))) xx(cancel((2v+1)(2v-1)))/ cancel((2v+5))#

#=1/v^2#