How do you divide \frac { 42x ^ { 4} } { 18x ^ { 7} }42x418x7?

1 Answer
Aug 3, 2017

7/(3x^3)73x3

Explanation:

First of all, simplify 42/184218

42/18 = 7/34218=73

So (42x^4)/(18x^7)42x418x7 can also be expressed as (7x^4)/(3x^7)7x43x7

Then, reduce the fraction with the powers by substracting them

x^7 - x^4 = x^3x7x4=x3

And the question is where do you place the x^3x3 ? Well, it is part of the denominator with the 77 because x^7x7 was the biggest between x^4x4 so it goes to the denominator

The final answer is : 7/(3x^3)73x3