How do you divide #\frac { 9x ^ { 5} + 18x ^ { 4} } { x ^ { 2} + 12x + 20} \div \frac { 3x ^ { 2} - 3x } { x ^ { 2} - 100}#?

1 Answer
Binayaka C.
Oct 2, 2017

#(3x^3(x-10))/(x-1)#

Explanation:

#(9x^5+ 18x^4)/( x^2+12x+20) -:(3x^2-3x)/(x^2-100)# or

#(9x^4(x+2))/(( x+10)(x+2)) -:(3x(x-1))/((x+10)(x-10)# or

#(9x^4cancel((x+2)))/(cancel(( x+10))cancel((x+2))) * (cancel((x+10))(x-10))/(3x(x-1))#

#(3x^3(x-10))/(x-1)# [Ans]

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