Question

How do you divide `\frac { d ^ { 6} } { 3a } \div ( \frac { d ^ { 2} } { 6a ^ { 2} } \cdot \frac { a } { 3d ^ { 3} } )`?

Answer 1

`6d^7`

Explanation:

`d^6/(3a)-:(d^2/(6a^2)*a/(3d^3))`

`=d^6/(3a)xx(6a^2)/d^2xx(3d^3)/a`

`=(cancel(d^6)^(d^4))/cancel(3a)xxcancel(6a^2)^(2a)/cancel(d^2)xx(3d^3)/a`

`=d^4xxcancel(2a)^2xx(3d^3)/cancel(a)`

`=6d^7`