How do you divide \frac { t ^ { 0} u v ^ { 2} } { t u ^ { 0} v ^ { 0} \cdot t u ^ { 2} v ^ { 0} }?

1 Answer
Jan 23, 2018

v^2/(t^2u

Explanation:

Note that x^0 will always equal 1 as long as x!=0

This simplifies your expression a lot.

(cancelt^0uv^2)/(tcancelu^0cancelv^0*tu^2cancelv^0

Also note that when you cancel, there still remains the number 1 for each of the powers of 0.

(uv^2)/(t*tu^2)

Multiply the two t's in the denominator:

(uv^2)/(t^2u^2)

(canceluv^2)/(t^2cancelu^2u

Your simplest answer becomes v^2/(t^2u