How do you divide #\frac { t ^ { 0} u v ^ { 2} } { t u ^ { 0} v ^ { 0} \cdot t u ^ { 2} v ^ { 0} }#?

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Answer 1 · 2018-01-23T03:25:43

#v^2/(t^2u#

Note that #x^0# will always equal 1 as long as #x!=0#

This simplifies your expression a lot.

#(cancelt^0uv^2)/(tcancelu^0cancelv^0*tu^2cancelv^0#

Also note that when you cancel, there still remains the number 1 for each of the powers of 0.

#(uv^2)/(t*tu^2)#

Multiply the two t's in the denominator:

#(uv^2)/(t^2u^2)#

#(canceluv^2)/(t^2cancelu^2u#

Your simplest answer becomes #v^2/(t^2u#