How do you divide #\frac { x + 2} { 4x ( x - 6) } \div \frac { x - 2} { 3x ( x - 6) }#?

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Answer 1 · 2017-05-04T03:43:06

#(3x+6)/(4x-8)#
#x!={0, 6}#

Expression #= (x+2)/(4x(x-6)) div (x-2)/(3x(x-6))#

#= (x+2)/(4x(x-6)) xx (3x(x-6))/(x-2)#

If #x!=0#

#= (x+2)/(4cancelx(x-6)) xx (3cancelx(x-6))/(x-2)#

If #x!=6#

#= (x+2)/(4cancel((x-6))) xx (3cancel((x-6)))/(x-2)#

#:.# Expression #=(3(x+2))/(4(x-2))#

#=(3x+6)/(4x-8)#