How do you divide #\frac { x ^ { 2} - 9} { 2x - 2} \div \frac { x ^ { 2} + 6x + 9} { x ^ { 2} + 2x - 3}#?

1 Answer
salamat
Dec 30, 2016

#(x-3)/2#

Explanation:

#(x^2-9)/(2x-2) :-(x^2+6x+9)/(x^2+2x-3)#

#=(x^2-9)/(2x-2)*(x^2+2x-3)/(x^2+6x+9)# change the position because it is operation for fraction.

#=((x-3)cancel((x+3)))/(2cancel((x-1)))*(cancel((x-1))cancel((x+3)))/(cancel((x+3))cancel((x+3))#

#=(x-3)/2#

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