How do you divide (m^2n^3)/p^3 by (mp)/n^2?

1 Answer
Apr 19, 2016

=(mn^5)/p^4

Explanation:

As you will recall, to if you want to divide a fraction, you'll flip it, then multiply it e.g. 2 divide 1/2 = 2 * 2/1 = 2*2 = 4

In this case, we'll flip (mp)/n^2:
(m^2n^3)/p^3 divide (mp)/n^2=(m^2n^3)/p^3*n^2/(mp)
=((m^2n^3)(n^2))/((p^3)(mp))

Now there is a rule you'll need to know to go further: a^m*a^n=a^(m+n)

=(m^2n^5)/(p^4m)

And there's another rule you need to know: a^m/a^n=a^(m-n)

=(mn^5)/p^4

Note: If you wish for me to explain those rules and why they work, just say so