How do you divide #(m^3+6m^2+9m-5)div(m+1)# using synthetic division?

1 Answer
Mar 17, 2017

Answer:

The remainder is #=-9# and the quotient is #=m^2+5m+4#

Explanation:

Let's perform the synthetic division

#color(white)(aaaa)##-1##color(white)(aaaa)##|##color(white)(aaaa)##1##color(white)(aaaa)##6##color(white)(aaaa)##9##color(white)(aaaa)##-5#
#color(white)(aaaaaaaaaaaa)#________

#color(white)(aaaa)####color(white)(aaaaaaa)##|##color(white)(aaaa)####color(white)(aaa)##-1##color(white)(aa)##-5##color(white)(aaaa)##-4#
#color(white)(aaaaaaaaaaaa)#________
#color(white)(aaaa)####color(white)(aaaaaaa)##|##color(white)(aaaa)##1##color(white)(aaaa)##5##color(white)(aaaa)##4##color(white)(aaaa)##color(red)(-9)#

The remainder is #=-9# and the quotient is #=m^2+5m+4#