How do you divide sqrt(x^6)/sqrt(y^18)?

We have, $\frac{\sqrt{{x}^{6}}}{\sqrt{{y}^{18}}}$
$\frac{{x}^{6 / 3}}{{y}^{18 / 2}}$
$\frac{{x}^{2}}{{y}^{9}}$ which is the required answer.