# How do you divide sqrt8/ sqrt24?

You use the fact that the fraction of two square root is the square root of the fraction, i.e.: $\setminus \frac{\setminus \sqrt{a}}{\setminus \sqrt{b}} = \setminus \sqrt{\setminus \frac{a}{b}}$. So, in your case, you have
$\setminus \frac{\setminus \sqrt{8}}{\setminus \sqrt{24}} = \setminus \sqrt{\setminus \frac{8}{24}} = \setminus \sqrt{\setminus \frac{1}{3}}$.
If you want to write it in a different form, divide and multiply by $\sqrt{3}$ to get $\setminus \sqrt{\setminus \frac{1}{3}} = \setminus \frac{\setminus \sqrt{3}}{3}$