How do you divide #(x^3+6x^2-4x+3)div(x+2)#?

1 Answer
Feb 21, 2017

Answer:

The remainder is #=27# and the quotient is #x^2+4x-12#

Explanation:

We perform the synthetic division

#color(white)(aaaa)##-2##color(white)(aaaa)##|##color(white)(aaaa)##1##color(white)(aaaa)##6##color(white)(aaaaa)##-4##color(white)(aaa)##3#

#color(white)(aaaaaa)##color(white)(aaaaa)##|##color(white)(aaaaa)##color(white)(aa)##-2##color(white)(aaaa)##-8##color(white)(aaaa)##24#

#color(white)(aaaaaaaaaa)#------------------------------------------------------------

#color(white)(aaaa)##color(white)(aaaaaa)##color(white)(aaaaaa)##1##color(white)(aaaa)##4##color(white)(aaaa)##-12##color(white)(aaaa)##color(red)(27)#

The remainder is #=27#

The quotient is #=x^2+4x-12#