# How do you do (sin^4x - sin^2x cos^2x + cos^4x) ?

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In fact, the problem was: sin^6x + cos^6x = 1-3/4 sen^2 2x

But... I factor the identities but I do not remember what else to do.

(sin^2x + cos^2x) (sin^4x - sen^2xcos^2x + cos^4x)

In fact, the problem was: sin^6x + cos^6x = 1-3/4 sen^2 2x

But... I factor the identities but I do not remember what else to do.

(sin^2x + cos^2x) (sin^4x - sen^2xcos^2x + cos^4x)

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Nghi N.
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Jun 11, 2018

Call

Note.

Equation (1) becomes:

Finally,

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