How do you draw the graph of direct variation that includes the point (1,6) and write the equation of the line?

1 Answer
Aug 12, 2017

#"see explanation"#

Explanation:

#"a direct variation equation is of the form"#

#y=kxlarr" k is the constant of variation"#

#"to find k use the given condition"#

#(1,6)toy=6" when "x=1#

#y=kxrArrk=y/x=6/1=6#

#"equation is " color(red)(bar(ul(|color(white)(2/2)color(black)(y=6x)color(white)(2/2)|)))#

#"this is a linear equation, that is it's graph is a straight line"#

#"to graph this choose values of x and substitute into the "#
#"equation for corresponding values of y"#

#((ulx,uly),(-1,-6),(0,0),(1,6))#

#"plot the points "(-1,-6),(0,0),(1,6)#
#"and draw a straight line through them"#
graph{6x [-11.1, 11.1, -5.54, 5.56]}