# How do you draw the Lewis Structure of CH_2I_2?

The number of valence electrons are $4 \left(C\right) + 2 \left(H\right) + 14 \left(I\right)$ $=$ $20 \text{ valence electrons}$. There are 4 bonding electron pairs around carbon so tetrahedral geometry is enforced by $\text{VSEPR}$. Each iodine atom bears 3 lone pairs, and thus 12 bonding electrons + 8 non bonding electrons satisfies the electron count.