Question

How do you evaluate `0.50[ x + ( x + 0.25x ) ]`?

Answer 1

1.125x

Explanation:

Braces are to be removed from inner to outer in that order to evaluate.
`0.5[x+x+0.25x] color(white)((@@)` removing ( ) bracket
`0.50[2.25x]=0.50*2.25x=(50/100)*((225/100)x`
`(50*225*x)/((100)(100))=(1125cancel(0)x)/(1000cancel(0))=1.125x`