Question

How do you evaluate `0= t ( 3.9- 4.9t )`?

Answer 1

t=0 or/and t=`\frac{39}{49}`

Explanation:

You've already pretty much solved it.

Let the stuff outside the brackets equal 0 (since it's basically another bracket), giving you `t=0`

Then let the things inside the bracket equal 0, giving you `3.9-4.9t=0`

Rearrange for t in the second equation, which gives you `t=\frac{39}{49}`