Question

How do you evaluate `1/2 log_2 64 + 1/3 log_5 125`?

Answer 1

4

Explanation:

Use `log_aa=1 and log (a^m)=m log a`

The given expression is

`(1/2)log_2(2^6) + (1/3) log_5(5^3)=(1/2)6 log_2 2 + (1/3) 3 log_5 5=3+1=4`