How do you evaluate #1.5\times -0.21#?

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Answer 1 · 2018-03-18T08:04:43

#-0.315#

You are multiplying two decimal values.

To start, ignore the decimal points and multiply the numbers as you would normally:

#15 xx -21 = -315#

Count how many decimal places there were to start with:

#1color(blue)(.5) xx -0color(blue)(.21)" "larr# there are #3# places

Put the same number of places in the final answer:

#-0color(blue)(.315)#