Question

How do you evaluate `-10- 7s < - 3`?

Answer 1

See a solution process below:

Explanation:

Step 1) Add `color(red)(10)` to each side of the inequality to isolate the `s` term while keeping the inequality balanced:

`color(red)(10) - 10 - 7s < color(red)(10) - 3`

`0 - 7s < 7`

`-7s < 7`

Step 2) Divide each side of the inequality by `color(blue)(-7)` to solve for `s` while keeping the inequality balanced. However, because we are multiplying or dividing an inequality by a negative number we must reverse the inequality operator:

`(-7s)/color(blue)(-7) color(red)(>) 7/color(blue)(-7)`

`(color(blue)(cancel(color(black)(-7)))s)/cancel(color(blue)(-7)) color(red)(>) -1`

`s > -1`