How do you evaluate #-10- 7s < - 3#?

1 Answer
smendyka
Aug 4, 2017

See a solution process below:

Explanation:

Step 1) Add #color(red)(10)# to each side of the inequality to isolate the #s# term while keeping the inequality balanced:

#color(red)(10) - 10 - 7s < color(red)(10) - 3#

#0 - 7s < 7#

#-7s < 7#

Step 2) Divide each side of the inequality by #color(blue)(-7)# to solve for #s# while keeping the inequality balanced. However, because we are multiplying or dividing an inequality by a negative number we must reverse the inequality operator:

#(-7s)/color(blue)(-7) color(red)(>) 7/color(blue)(-7)#

#(color(blue)(cancel(color(black)(-7)))s)/cancel(color(blue)(-7)) color(red)(>) -1#

#s > -1#

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