How do you evaluate #(10\div ( - 9+ 6\times 5) ) \times ( - 2)#?

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Answer 1 · 2017-02-28T21:40:54

#-20/21#

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#(10 divide (-9 + 30)) times (-2)#

#(10 divide 21) times (-2)#

#-20/21#

Answer 2 · 2017-03-01T14:25:00

#-20/21#

#(10-:(-9+6 xx 5)) xx (-2))#

#:.=(10-:(-9+30)) xx (-2))#

#:.=10-:21 xx -2#

#:.=10 xx 1/21 xx -2#

#:.=10/21 xx -2/1#

#:.=-20/21#