How do you evaluate #(10x ^ { 6} - 12x ^ { 5} + 18x ^ { 4} - 20x ^ { 3} ) \div ( 2x ^ { 7} )#?

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Answer 1 · 2017-01-02T12:08:11

#5x^-1-6x^-2+9x^-3-10x^-4#

#(10x^6-12x^5+18x^4-20x^3)-:(2x^7)#

by long division:

#(10x^6-12^5+18x^4-20x^3)/(2x^7)#

#=5x^-1-6x^-2+9x^-3-10x^-4#

check:

#2x^7(5x^-1-6x^-2+9x^-3-10x^-4)#

#=(10x^(-1+7)-12x^(-2+7)+18x^(-3+7)-20x^(-4+7))#

#=(10x^6-12x^5+18x^4-20x^3)#

Take note: #a^3*a^4=a^(3+4)# and #a^m/a^n=a^(m-n)# #m>n#