How do you evaluate #(12+48)\times 2\div (13+7)-2^{5}#?

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Answer 1 · 2017-09-22T13:24:10

#-26#

There are #2# terms.

Calculate an answer for each term first.

Within each term do:
Brackets first, then powers, multiply or divide, add or subtract.

#color(red)((12+48))xx2 div(color(red)(13+7))-color(blue)(2^5)#

=#color(red)((60))xx2 div(color(red)(20))-color(blue)(32)#

#= (cancel60^3xx2)/cancel20-color(blue)(32)" "or (120/20)#

#=6-32#

#= -26#