How do you evaluate #13,797\div 27#?

1 Answer
Apr 10, 2017

#511#

Explanation:

#color(blue)"Note that " 27=3xx9#

So that dividing by 3 then 9 or 9 then 3 is the same as dividing by 27 but 'hopefully' a lot easier.

Using any available method you have for #color(blue)"short division"#

#" I prefer "color(blue)"cancelling"# so will use that method.

#rArr13797/3=cancel(13797)^color(red)(4599)/cancel(3)^1#

#rArrcancel(4599)^(color(red)(511))/cancel(9)^1=511#

#"Thus " 13797-:27=511#