How do you evaluate #14 1/ 2- 7\frac { 11} { 18}#?

2 Answers
Dec 15, 2017

Method 1 of 2

#6 8/9#

Explanation:

Multiply by 1 and you do not change the value. However, 1 comes in many forms. So you can change the way a number looks without changing its intrinsic value.

The bottom number in a fraction has the name denominator. In reality it is a sort of unit of measurement. Consequently you can not DIRECTLY add or subtract the top numbers unless the units of measurement (denominators) are the same.

#color(blue)("Making the denominators the same") #

#color(brown)("Consider the "14 1/2" write as "14+1/2)#

#color(green)([14color(red)(xx1)]+1/2 )#

#color(green)([14color(red)(xx2/2)]+1/2 )#

#color(green)([28/2]+1/2 =29/2 )#

but this denominator (unit of measurement) does not match that of#7 11/18#

#color(green)(29/2color(red)(xx1)=29/2color(red)(xx9/9)=261/18 )#
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(brown)("Consider the "7 11/18)#

#color(green)("Using the above method we have "7 11/18 = 137/18)#

#"===================================="#
#color(blue)("Putting it all together")#

#261/18-137/18color(white)("d")=color(white)("d")(261-137)/18color(white)("d")= color(white)("d")124/18color(white)("d")=color(white)("d")6 8/9#

color(white)("d")

Dec 15, 2017

Method 2 of 2

It take longer to explain that actually doing the maths.

#6 8/9#

Explanation:

#color(blue)("Method")#

Directly subtract whole number from whole number and fraction from fraction.
~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Preperation")#

Starting point: #(14-7)+(1/2-11/18)#

Note that #1/2# is the same as #9/18# so we have:

#(14-7)+(9/18-11/18)#
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Doing the maths")#

But #9/18# is less than #11/18# so lets move a 1 from the 14 giving

#(13-7)+(1+9/18-11/18)#

#(13-7)+(18/18+9/18-11/18)#

#(6)+(7/18+9/18)#

#6+(16/18)#

#6+((16-:2)/(18-:2))#

#6 8/9#