How do you evaluate #-2( 0.14) ( - 3) ( 0.5)#?

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Answer 1 · 2017-09-13T12:32:20

#0.42#

#(((−2)xx(0.14))xx(−3))xx(0.5)#

#=((−0.28)xx(−3))xx(0.5)#

#=(0.84)xx(0.5)#

#=0.42#

Answer 2 · 2017-09-13T12:32:51

#color(red)(0.42)#

#-2(0.14)(-3)(0.5)#

#color(white)("XXX")=2xx(0.14)xx(3)xx(0.5)color(white)("xxx")#multiplying 2 negatives gives a positive

#color(white)("XXX")=(0.14)xx(3)xx(2)xx(0.5)color(white)("xxx")#rearrange to simplify

#color(white)("XXX")=(0.14)xx(3)color(white)("xxxxxxxxxxxxxx"#since #2xx0.5=1#

#color(white)("XXX")=0.42#