How do you evaluate #-\{ - ( - 2) ] - ( - 1) - 5+ (64/27)^(1/3) #?

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Answer 1 · 2018-01-20T11:41:54

#-6 2/3#

#-{-(-2)}-(-1)-5+(64/27)^(1/3)#

#:.=-2+1-5+root3(64/27)#

#:.=-9+1+root3(2*2*2*2*2*2)/(3*3*3)#

#:.=root3(2)=2,root3(3)=3#

#:.=-8+4/3#

#:.=-24/3+4/3#

#:.=-20/3#

#:.=-6 2/3#