How do you evaluate #2( 4\cdot 3+ 5) + 8( 3\cdot 3+ 1)#?

2 Answers
Aug 13, 2017

See a solution process below:

Explanation:

First, execute the Multiplication within the Parenthesis:

#2(color(red)(4 * 3) + 5) + 8(color(blue)(3 * 3) + 1) => 2(12 + 5) + 8(9 + 1)#

Next, execute the Addition within the Parenthesis:

#2(color(red)(12 + 5)) + 8(color(blue)(9 + 1)) => 2 * 17 + 8 * 10#

Then, execute the Multiplication left to right:

#color(red)(2 * 17) + color(blue)(8 * 10) => 34 + color(blue)(8 * 10) => 34 + 80#

Now, execute the Addition:

# 34 + 80 => 114#

Aug 13, 2017

See below

Explanation:

First you need to know some rules that have to be used in this type of questions!
#BIDMAS#
#B# -brackets
#I# -Indices
#D# -division
#M# -multiplication
#A# - add
#S# -substract

The first thing to do now for this question is to do everything inside the #BRACKETS#( which comes first in BIDMAS).
#(4*3)#=#12#
You also have an add sign in your brackets which means that you need to add that number to the above answer.
So: #(12+5)=17#
The next step is to multiply #2# (the number outside the bracket,at the begining of the question) because there isn't any sign between the bracket and the number therefore in maths it means you will have to do multiplication.
Therefore: #2*17=34#

The next step is exastly the same.
Multiply inside the bracket: #3*3=9#
Add the number inside the bracket to your multiplication answer: #9+1=10#
Then multiply the number outside the bracket which is #8# by the result you have inside the brackets!
#8*10=80#

Once you have the two answers #34# and #80# you need to add them together because this is what it is asking you to do between the two brackets.
Therefore: #34+80=114#
#114# is the answer to this question!

I hope this will help you in future!