How do you evaluate #(2+ 5) ^ { 2} + ( 18\div 6)#?

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Answer 1 · 2017-10-24T01:59:41

52

To solve this equation, you use PEMDAS, or (parenthesis, exponent, multiplication/division, and addition/subtraction in that order)

The first thing that comes up here are things in a parenthesis, so
#(2+5)^2 + (18 -: 6)# becomes
#7^2 + 3#

Now we need to simplify the exponent on the 7, so we get:
#49 + 3#

Final answer: #52#

Answer 2 · 2017-10-24T02:00:37

52

First simplify the braces.

#(2+5)^2 + (18/6) = 7^2 + 3#

#(7*7) + 3#

#= 49 + 3 = 52#