# How do you evaluate (2.9times10^-2)(5.2times10^-9)?

Aug 2, 2017

The 'normal' parts are multiplied and the exponents are added.
1.5 xx10^(−10)

#### Explanation:

Remember that exponents are just a way to simplify writing very large and very small numbers. They do not change the way the numbers combine in mathematics. The rules for combination do have to be observed.

(2.9 × 10^(−2))xx(5.2 × 10^(−9))

(2.9 × 5.2) xx(10^(−2) × 10^(−9))

(15.08) xx(10^(−11))

1.5 xx10^(−10)

The "longhand" version would be a simple multiplication:

$0.029 \times 0.0000000052 = 0.00000000015$