How do you evaluate #[2\cdot 2( 2+ 1) ] ^ { 2} #?

1 Answer
Mar 3, 2018

#144#

Explanation:

We can start by combining the terms in the parenthesis to get #3#. Our new problem is as follows:

#[2*2(3)]^2#

We multiply #2*3# next to get #6#. We would then multiply this by #2# to get:

#[12]^2#

Squaring #12#, we get #144#.