Question

How do you evaluate `2^(log_2 12)`?

Answer 1

12

Explanation:

Let `a = 2^(log_2 12)`.

Then, `log_2 a`

`= log_2 2^(log_2 12)`

`=log_2 12 log_2 2=`

`=log_2 12`.

Log function is single-valued. So, a = 12.