Question

How do you evaluate `2 log_3 12 - 2 log_3 4`?

Answer 1

I found: `2`

Explanation:

I would use the properties of logs and write:

`log_3(12)^color(red)(2)-log_3(4)^color(red)(2)=`

and then:

`=log_3(12/4)^2=log_3(3^2)=2`