How do you evaluate #2(n)^2 + 1# if n = 5? Algebra Expressions, Equations, and Functions Variable Expressions 1 Answer sente Dec 21, 2015 Substitute #5# for #n# and evaluate the expression using the order of operations to find #2n^2+1 = 51# for #n=5# Explanation: Plugging in #5# for #n# and following the order of operations (exponents before multiplication before addition): #2(5)^2 + 1 = 2(25)+1# #= 50+1# #= 51# Answer link Related questions How do you write the variable expression for: a quotient of 2 and the sum of a number and 3 ? What are variables? What are variable expressions? How do you write variable expressions? How do you evaluate variable expressions? How do you simplify the expression #3x-x+4#? How do you write a quotient of a number and 6 as an expression? How do you evaluate the expression #2x+1# for #x=1#? How do you write a product of a number and 2 as an expression? How do you write 5 less than 2 times a number as a variable expression? See all questions in Variable Expressions Impact of this question 1456 views around the world You can reuse this answer Creative Commons License