How do you evaluate #(2+ \sqrt { 3} ) ( \sqrt { 2} + 3)#?

1 Answer
smendyka
Sep 25, 2017

See a solution process below:

Explanation:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(2) + color(red)(sqrt(3)))(color(blue)(sqrt(2)) + color(blue)(3))# becomes:

#(color(red)(2) xx color(blue)(sqrt(2))) + (color(red)(2) xx color(blue)(3)) + (color(red)(sqrt(3)) xx color(blue)(sqrt(2))) + (color(red)(sqrt(3)) xx color(blue)(3))#

#2sqrt(2) + 6 + sqrt(3 * 2) + 3sqrt(3)#

#2sqrt(2) + 6 + sqrt(6) + 3sqrt(3)#

#sqrt(6) + 3sqrt(3) + 2sqrt(2) + 6#

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