How do you evaluate #2\sqrt { 3} - \sqrt { 8} - 3\sqrt { 2}#?

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Answer 1 · 2017-03-23T16:51:56

#2sqrt(3)-5sqrt(2)#

Factor the 8 inside the square root:

#2sqrt(3)-sqrt(2xx2xx2)-3sqrt(2)#

Take out a 2 from inside that square root:

#2sqrt(3)-2sqrt(2)-3sqrt(2)#

Now combine the two #sqrt2#

#2sqrt(3)+(-2-3)sqrt(2)#

#2sqrt(3)-5sqrt(2)#