How do you evaluate #(27\div 9) ^ { 2} - 4#?

1 Answer
Meave60
Mar 22, 2017

The answer is #5#.

Explanation:

Apply the order of operations: parentheses/brackets; exponents/powers; multiplication and division from left to right; addition and subtraction from left to right. A way to remember this is the acronym PEMDAS.

#(27-:9)^2-4#

Carry out the operation within the parentheses.

#(3)^2-4#

Apply the exponent.

#3^2-4#

#9-4#

Subtract #4# from #9#.

#5#

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