How do you evaluate #2ac-b^2*-3a# for #a=2,b=-3# and #c=4#?
1 Answer
Aug 28, 2016
70
Explanation:
This expression involves subtraction and multiplication.
Consider
#color(blue)"PEDMAS"# which informs us that we must perform multiplication before subtraction.
#rArr2ac-b^2xx(-3a)=2ac+3ab^2# substitute the appropriate values into the expression.
#rArr2ac+3ab^2=(2xx2xx4)+(3xx2xx(-3)^2)#
#=16+(3xx2xx9)=16+54=70#
