How do you evaluate #(2c^3-ab)/4# given a=12, b=9, c=4?

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Answer 1 · 2017-06-30T12:06:50

See a solution process below:

To evaluate this expression substitute:

#color(red)(12)# for #color(red)(a)#

#color(blue)(9)# for #color(blue)(b)#

#color(green)(4)# for #color(green)(c)#

#(2color(green)(c)^3 - color(red)(a)color(blue)(b))/4# becomes:

#((2 xx color(green)(4)^3) - (color(red)(12) xx color(blue)(9)))/4 =>#

#((2 xx color(green)(64)) - 108)/4 =>#

#(128 - 108)/4 =>#

#20/4 =>#

#5#

Answer 2 · 2017-06-30T12:46:00

#5#

#"substitute the given values into the expression"#

#=((2xx4^3)-(12xx9))/4#

#=(128-108)/4#

#=20/4#

#=5#