How do you evaluate #(2c + 5) ( 5c + 3) #?

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Answer 1 · 2017-10-31T02:06:06

See a solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(2c) + color(red)(5))(color(blue)(5c) + color(blue)(3))# becomes:

#(color(red)(2c) xx color(blue)(5c)) + (color(red)(2c) xx color(blue)(3)) + (color(red)(5) xx color(blue)(5c)) + (color(red)(5) xx color(blue)(3))#

#10c^2 + 6c + 25c + 15#

We can now combine like terms:

#10c^2 + (6 + 25)c + 15#

#10c^2 + 31c + 15#