How do you evaluate #2s^3+r-t# given r=-3, s=4, t=-7?

1 Answer
Oct 27, 2016

#124#

Explanation:

Given the expression:
#color(white)("XXX")2color(red)s^3+color(blue)r-color(green)t#
with
#color(white)("XXX")color(red)(s=4)#
#color(white)("XXX")color(blue)(r=-3)#
#color(white)("XXX")color(green)(t=-7)#

The expression becomes:
#color(white)("XXX")2(color(red)4)^3-(color(blue)(-3))+(color(green)(-7))#

#color(white)("XXX")=128+3-7#

#color(white)("XXX")=124#