How do you evaluate #3^ { - 2} + 4^ { - 1}#?

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Answer 1 · 2017-02-23T08:34:51

#13/36#

We can start by remembering that #x^(-1)=1/x#:

#3^(-2)+4^(-1)#

#1/(3^2)+1/(4^1)#

We can now evaluate the powers:

#1/9+1/4#

Next let's find a common denominator:

#1/9(1)+1/4(1)#

#1/9(4/4)+1/4(9/9)#

#4/36+9/36=13/36#