Question

How do you evaluate `(3^ { 2} - 6 + 3) \times 8`?

Answer 1

`48`

Explanation:

This is all one term, but there are different operations to be done,

Take care to do them in the correct order:

`(color(red)(3^2)-6+3)xx8 = (color(red)(9)-6+3)xx8" "larr` powers inside the bracket first

`(color(blue)(9-6+3))xx8=(color(blue)(6))xx8" "larr` answer for the bracket

`6 xx8 =48`