How do you evaluate #(-3/2)+(8/5)#? Prealgebra Negative Numbers and Absolute Value Negative Numbers 1 Answer Chenyang Mar 3, 2018 #(-3/2)+(8/5)# = #1/10# Explanation: #(-3/2)+(8/5)# = #(-15/10)+(16/10)# =#16/10 -15/10 # =#1/10# Answer link Related questions How do you compute #-8+13#? How do you compute #11+(-19)#? How do you compute #-19-8#? How do you compute #-77+(-46)#? How do you compute #41+(-56)#? How do you compute #50-82#? How do you compute #-47-13#? How do you compute #-80+102#? How do you compute #5(18)#? How do you compute #-64div(-8)#? See all questions in Negative Numbers Impact of this question 2536 views around the world You can reuse this answer Creative Commons License