How do you evaluate #(3+ 5) ^ { 2} - 2\cdot 7#?

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Answer 1 · 2018-03-21T06:49:59

#50#

To simplify this expression, all we need to do, is use #PEMDAS#.

First thing we need to know is the definition of #PEMDAS#:

#P# - Parenthesis

#MD# - Multiply/Divide (Left to Right)

#AS# - Add/Subtract (Left to Right)

This is the order we must do this, from top to bottom. This process is more commonly known as the Order of Operations .

Now that we know the order of the steps we must take to solve this, this is the solution:

#(3+5)^2-2*7#

#=(8)^2-2*7#

#=64-2*7#

#=64-14#

#=50#