How do you evaluate -3√6-√12+3√3?

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Answer 1 · 2015-11-09T04:45:25

Addition of radical terms

First of all,you've to simplify the equation,

#-3sqrt6 - sqrt12 + 3sqrt3#

#-3sqrt6 - sqrt(3xx4) + 3sqrt3#

#-3sqrt6 - (sqrt3 xx sqrt4) + 3sqrt3#

#-3sqrt6 - (2 xx sqrt3) + 3sqrt3#

#-3sqrt6 - 2sqrt3 + 3sqrt3#

Then, plus/minus the same radical terms

Thus,the answer is

#-3sqrt6 + sqrt3#