How do you evaluate -3√6-√12+3√3?

1 Answer

Answer:

Addition of radical terms

Explanation:

First of all,you've to simplify the equation,

#-3sqrt6 - sqrt12 + 3sqrt3#

#-3sqrt6 - sqrt(3xx4) + 3sqrt3#

#-3sqrt6 - (sqrt3 xx sqrt4) + 3sqrt3#

#-3sqrt6 - (2 xx sqrt3) + 3sqrt3#

#-3sqrt6 - 2sqrt3 + 3sqrt3#

Then, plus/minus the same radical terms

Thus,the answer is

#-3sqrt6 + sqrt3#