How do you solve #-3( k + 2) = 2- 3k#?

1 Answer
Sep 15, 2017

You can't, because at the end, both sides are different.

There is no solution.

Explanation:

First thing to do is to expand the left side... so:

#-3k+(-3*2)=2-3k#

#" "-3k-6=2-3k" "# Add #3k+6# to both sides.

#-3k-6+3k+6=2-3k+3k+6#

#0=8#

This equation makes you end up with unequal sides, and there is no variable so you cannot solve this.