Question

How do you evaluate `3 log_2 (6) - 3/4 log_2 (81)`?

Answer 1

It is

#3 log_2 (6) - 3/4 log_2 (81)=3log_2 6-3/4*log_2 3^4= log_2 6^3-3/4*4*log_2 3=log_2 6^3-3/(cancel4) (cancel4)*log_2 3= log_2 6^3-log_2 3^3=log_2 (6/3)^3= log_2 (2)^3=3*log_2 2=3#