How do you evaluate #3\log _ { 3} 2+ 2\log _ { 3} 2- \frac { 2} { 3} \log _ { 3} 64#?

1 Answer
P dilip_k
Nov 10, 2017

#3\log _ { 3} 2+ 2\log _ { 3} 2- \frac { 2} { 3} \log _ { 3} 64#

#=3\log _ { 3} 2+ 2\log _ { 3} 2- log _ { 3} (2^6)^(2/3)#

#=3\log _ { 3} 2+ 2\log _ { 3} 2- log _ { 3} (2^4)#

#=5\log _ { 3} 2- 4log _ { 3} 2#

#=log _ { 3} 2#

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